(4-v)-(11+2v=)

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Solution for (4-v)-(11+2v=) equation: 



(4-v)-(11+2v=)

We move all terms to the left:

(4-v)-(11+2v-())=0

We add all the numbers together, and all the variables

(-1v+4)-(11+2v-())=0

We get rid of parentheses

-1v-(11+2v-())+4=0



We calculate terms in parentheses: -(11+2v-()), so:

11+2v-()

determiningTheFunctionDomain
2v+11-()

We add all the numbers together, and all the variables

2v

Back to the equation:

-(2v)



We add all the numbers together, and all the variables

-3v+4=0

We move all terms containing v to the left, all other terms to the right

-3v=-4

v=-4/-3

v=1+1/3

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