(4-g)-3(2g-6)=8(3g-1)-11(g-5)

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Solution for (4-g)-3(2g-6)=8(3g-1)-11(g-5) equation: 



(4-g)-3(2g-6)=8(3g-1)-11(g-5)

We move all terms to the left:

(4-g)-3(2g-6)-(8(3g-1)-11(g-5))=0

We add all the numbers together, and all the variables

(-1g+4)-3(2g-6)-(8(3g-1)-11(g-5))=0

We multiply parentheses

(-1g+4)-6g-(8(3g-1)-11(g-5))+18=0

We get rid of parentheses

-1g-6g-(8(3g-1)-11(g-5))+4+18=0



We calculate terms in parentheses: -(8(3g-1)-11(g-5)), so:

8(3g-1)-11(g-5)

We multiply parentheses

24g-11g-8+55

We add all the numbers together, and all the variables

13g+47

Back to the equation:

-(13g+47)



We add all the numbers together, and all the variables

-7g-(13g+47)+22=0

We get rid of parentheses

-7g-13g-47+22=0

We add all the numbers together, and all the variables

-20g-25=0

We move all terms containing g to the left, all other terms to the right

-20g=25

g=25/-20

g=-1+1/4

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