(4-9i)/(1-3i)

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Solution for (4-9i)/(1-3i) equation: 


D( i )

1-(3*i) = 0

1-(3*i) = 0

1-(3*i) = 0

1-3*i = 0

1-3*i = 0 // - 1

-3*i = -1 // : -3

i = -1/(-3)

i = 1/3

i in (-oo:1/3) U (1/3:+oo)

(4-(9*i))/(1-(3*i)) = 0

(4-9*i)/(1-3*i) = 0

4-9*i = 0 // - 4

-9*i = -4 // : -9

i = -4/(-9)

i = 4/9

i = 4/9

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