(4-4x)(x*3+2)=0

Solution for (4-4x)(x*3+2)=0 equation:

(4-4x)(x*3+2)=0

We add all the numbers together, and all the variables

(-4x+4)(x*3+2)=0

We multiply parentheses ..

(-12x^2-8x+12x+8)=0

We get rid of parentheses

-12x^2-8x+12x+8=0

We add all the numbers together, and all the variables

-12x^2+4x+8=0

a = -12; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·(-12)·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*-12}=\frac{-24}{-24}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*-12}=\frac{16}{-24}
=-2/3
$