(4-3x)/5=(x-0.2)/0.5

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Solution for (4-3x)/5=(x-0.2)/0.5 equation: 



(4-3x)/5=(x-0.2)/0.5

We move all terms to the left:

(4-3x)/5-((x-0.2)/0.5)=0

We add all the numbers together, and all the variables

(-3x+4)/5-((x-0.2)/0.5)=0

We calculate fractions


(-3x)/()+(-((x-0.2)*5)/()=0



We calculate terms in parentheses: +(-((x-0.2)*5)/(), so:

-((x-0.2)*5)/(

We multiply all the terms by the denominator


-((x-0.2)*5)



We calculate terms in parentheses: -((x-0.2)*5), so:

(x-0.2)*5

We multiply parentheses

5x-1

Back to the equation:

-(5x-1)



We get rid of parentheses

-5x+1

Back to the equation:

+(-5x+1)



We get rid of parentheses

(-3x)/()-5x+1=0

We multiply all the terms by the denominator


(-3x)-5x*()+1*()=0

We add all the numbers together, and all the variables

(-3x)-5x*()=0

We get rid of parentheses

-3x-5x*()=0

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