(4-3x)(4-3x)=9x*9x

Solution for (4-3x)(4-3x)=9x*9x equation:

(4-3x)(4-3x)=9x*9x

We move all terms to the left:

(4-3x)(4-3x)-(9x*9x)=0

We add all the numbers together, and all the variables

(-3x+4)(-3x+4)-(+9x*9x)=0

We get rid of parentheses

(-3x+4)(-3x+4)-9x*9x=0

We multiply parentheses ..

(+9x^2-12x-12x+16)-9x*9x=0

Wy multiply elements

(+9x^2-12x-12x+16)-81x^2=0

We get rid of parentheses

9x^2-81x^2-12x-12x+16=0

We add all the numbers together, and all the variables

-72x^2-24x+16=0

a = -72; b = -24; c = +16;
Δ = b2-4ac
Δ = -242-4·(-72)·16
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-72}{2*-72}=\frac{-48}{-144}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+72}{2*-72}=\frac{96}{-144}
=-2/3
$