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(4-3(2x-1))=-(5x-2(2x+3))
We move all terms to the left:
(4-3(2x-1))-(-(5x-2(2x+3)))=0
We calculate terms in parentheses: +(4-3(2x-1)), so:
4-3(2x-1)
determiningTheFunctionDomain -3(2x-1)+4
We multiply parentheses
-6x+3+4
We add all the numbers together, and all the variables
-6x+7
Back to the equation:
+(-6x+7)
We calculate terms in parentheses: -(-(5x-2(2x+3))), so:We get rid of parentheses
-(5x-2(2x+3))
We calculate terms in parentheses: -(5x-2(2x+3)), so:We get rid of parentheses
5x-2(2x+3)
We multiply parentheses
5x-4x-6
We add all the numbers together, and all the variables
x-6
Back to the equation:
-(x-6)
-x+6
We add all the numbers together, and all the variables
-1x+6
Back to the equation:
-(-1x+6)
-6x+1x+7-6=0
We add all the numbers together, and all the variables
-5x+1=0
We move all terms containing x to the left, all other terms to the right
-5x=-1
x=-1/-5
x=1/5
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