(4-2i)(4+2i)=

Solution for (4-2i)(4+2i)= equation:

Simplifying
(4 + -2i)(4 + 2i) = 0

Multiply (4 + -2i) * (4 + 2i)
(4(4 + 2i) + -2i * (4 + 2i)) = 0
((4 * 4 + 2i * 4) + -2i * (4 + 2i)) = 0
((16 + 8i) + -2i * (4 + 2i)) = 0
(16 + 8i + (4 * -2i + 2i * -2i)) = 0
(16 + 8i + (-8i + -4i2)) = 0

Combine like terms: 8i + -8i = 0
(16 + 0 + -4i2) = 0
(16 + -4i2) = 0

Solving
16 + -4i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -4i2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -4i2 = 0 + -16
-4i2 = 0 + -16

Combine like terms: 0 + -16 = -16
-4i2 = -16

Divide each side by '-4'.
i2 = 4

Simplifying
i2 = 4

Take the square root of each side:
i = {-2, 2}