(4+y)(5y+2)=0

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Solution for (4+y)(5y+2)=0 equation: 


Simplifying
(4 + y)(5y + 2) = 0

Reorder the terms:
(4 + y)(2 + 5y) = 0

Multiply (4 + y) * (2 + 5y)
(4(2 + 5y) + y(2 + 5y)) = 0
((2 * 4 + 5y * 4) + y(2 + 5y)) = 0
((8 + 20y) + y(2 + 5y)) = 0
(8 + 20y + (2 * y + 5y * y)) = 0
(8 + 20y + (2y + 5y2)) = 0

Combine like terms: 20y + 2y = 22y
(8 + 22y + 5y2) = 0

Solving
8 + 22y + 5y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + y)(2 + 5y) = 0


Subproblem 1
Set the factor '(4 + y)' equal to zero and attempt to solve:

Simplifying
4 + y = 0

Solving
4 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + y = 0 + -4
y = 0 + -4

Combine like terms: 0 + -4 = -4
y = -4

Simplifying
y = -4

Subproblem 2
Set the factor '(2 + 5y)' equal to zero and attempt to solve:

Simplifying
2 + 5y = 0

Solving
2 + 5y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5y = 0 + -2
5y = 0 + -2

Combine like terms: 0 + -2 = -2
5y = -2

Divide each side by '5'.
y = -0.4

Simplifying
y = -0.4
Solution
y = {-4, -0.4}

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