(4+y)(3y+1)=0

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Solution for (4+y)(3y+1)=0 equation:


Simplifying
(4 + y)(3y + 1) = 0

Reorder the terms:
(4 + y)(1 + 3y) = 0

Multiply (4 + y) * (1 + 3y)
(4(1 + 3y) + y(1 + 3y)) = 0
((1 * 4 + 3y * 4) + y(1 + 3y)) = 0
((4 + 12y) + y(1 + 3y)) = 0
(4 + 12y + (1 * y + 3y * y)) = 0
(4 + 12y + (1y + 3y2)) = 0

Combine like terms: 12y + 1y = 13y
(4 + 13y + 3y2) = 0

Solving
4 + 13y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + y)(1 + 3y) = 0

Subproblem 1

Set the factor '(4 + y)' equal to zero and attempt to solve: Simplifying 4 + y = 0 Solving 4 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + y = 0 + -4 y = 0 + -4 Combine like terms: 0 + -4 = -4 y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(1 + 3y)' equal to zero and attempt to solve: Simplifying 1 + 3y = 0 Solving 1 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3y = 0 + -1 3y = 0 + -1 Combine like terms: 0 + -1 = -1 3y = -1 Divide each side by '3'. y = -0.3333333333 Simplifying y = -0.3333333333

Solution

y = {-4, -0.3333333333}

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