(4+x)/6=(x-3)/8

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Solution for (4+x)/6=(x-3)/8 equation: 



(4+x)/6=(x-3)/8

We move all terms to the left:

(4+x)/6-((x-3)/8)=0

We add all the numbers together, and all the variables

(x+4)/6-((x-3)/8)=0

We calculate fractions


x/()+(-((x-3)*6)/()=0



We calculate terms in parentheses: +(-((x-3)*6)/(), so:

-((x-3)*6)/(

We multiply all the terms by the denominator


-((x-3)*6)



We calculate terms in parentheses: -((x-3)*6), so:

(x-3)*6

We multiply parentheses

6x-18

Back to the equation:

-(6x-18)



We get rid of parentheses

-6x+18

Back to the equation:

+(-6x+18)



We get rid of parentheses

x/()-6x+18=0

We multiply all the terms by the denominator


x-6x*()+18*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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