(4+x)(3x-2)=0

Solution for (4+x)(3x-2)=0 equation:

(4+x)(3x-2)=0

We add all the numbers together, and all the variables

(x+4)(3x-2)=0

We multiply parentheses ..

(+3x^2-2x+12x-8)=0

We get rid of parentheses

3x^2-2x+12x-8=0

We add all the numbers together, and all the variables

3x^2+10x-8=0

a = 3; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·3·(-8)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*3}=\frac{4}{6}
=2/3
$