(4+u)(2u-3)=0

Solution for (4+u)(2u-3)=0 equation:

Simplifying
(4 + u)(2u + -3) = 0

Reorder the terms:
(4 + u)(-3 + 2u) = 0

Multiply (4 + u) * (-3 + 2u)
(4(-3 + 2u) + u(-3 + 2u)) = 0
((-3 * 4 + 2u * 4) + u(-3 + 2u)) = 0
((-12 + 8u) + u(-3 + 2u)) = 0
(-12 + 8u + (-3 * u + 2u * u)) = 0
(-12 + 8u + (-3u + 2u2)) = 0

Combine like terms: 8u + -3u = 5u
(-12 + 5u + 2u2) = 0

Solving
-12 + 5u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-4 + -1u)(3 + -2u) = 0

Subproblem 1
Set the factor '(-4 + -1u)' equal to zero and attempt to solve:

Simplifying
-4 + -1u = 0

Solving
-4 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1u = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1u = 0 + 4
-1u = 0 + 4

Combine like terms: 0 + 4 = 4
-1u = 4

Divide each side by '-1'.
u = -4

Simplifying
u = -4
Subproblem 2
Set the factor '(3 + -2u)' equal to zero and attempt to solve:

Simplifying
3 + -2u = 0

Solving
3 + -2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2u = 0 + -3
-2u = 0 + -3

Combine like terms: 0 + -3 = -3
-2u = -3

Divide each side by '-2'.
u = 1.5

Simplifying
u = 1.5
Solution
u = {-4, 1.5}