(4+r)/9=(r+3)/45

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Solution for (4+r)/9=(r+3)/45 equation: 



(4+r)/9=(r+3)/45

We move all terms to the left:

(4+r)/9-((r+3)/45)=0

We add all the numbers together, and all the variables

(r+4)/9-((r+3)/45)=0

We calculate fractions


r/()+(-((r+3)*9)/()=0



We calculate terms in parentheses: +(-((r+3)*9)/(), so:

-((r+3)*9)/(

We multiply all the terms by the denominator


-((r+3)*9)



We calculate terms in parentheses: -((r+3)*9), so:

(r+3)*9

We multiply parentheses

9r+27

Back to the equation:

-(9r+27)



We get rid of parentheses

-9r-27

Back to the equation:

+(-9r-27)



We get rid of parentheses

r/()-9r-27=0

We multiply all the terms by the denominator


r-9r*()-27*()=0

We add all the numbers together, and all the variables

r-9r*()=0

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