(4+n)+6=(n+4)+6

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Solution for (4+n)+6=(n+4)+6 equation: 



(4+n)+6=(n+4)+6

We move all terms to the left:

(4+n)+6-((n+4)+6)=0

We add all the numbers together, and all the variables

(n+4)-((n+4)+6)+6=0

We get rid of parentheses

n-((n+4)+6)+4+6=0



We calculate terms in parentheses: -((n+4)+6), so:

(n+4)+6

We get rid of parentheses

n+4+6

We add all the numbers together, and all the variables

n+10

Back to the equation:

-(n+10)



We add all the numbers together, and all the variables

n-(n+10)+10=0

We get rid of parentheses

n-n-10+10=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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