(4+8i)(2+4i)=0

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Solution for (4+8i)(2+4i)=0 equation: 



(4+8i)(2+4i)=0

We add all the numbers together, and all the variables

(8i+4)(4i+2)=0

We multiply parentheses ..

(+32i^2+16i+16i+8)=0

We get rid of parentheses

32i^2+16i+16i+8=0

We add all the numbers together, and all the variables

32i^2+32i+8=0

a = 32; b = 32; c = +8;
Δ = b2-4ac
Δ = 322-4·32·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-32}{64}=-1/2$

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