(4+6i)(2-3i)=

Solution for (4+6i)(2-3i)= equation:

Simplifying
(4 + 6i)(2 + -3i) = 0

Multiply (4 + 6i) * (2 + -3i)
(4(2 + -3i) + 6i * (2 + -3i)) = 0
((2 * 4 + -3i * 4) + 6i * (2 + -3i)) = 0
((8 + -12i) + 6i * (2 + -3i)) = 0
(8 + -12i + (2 * 6i + -3i * 6i)) = 0
(8 + -12i + (12i + -18i2)) = 0

Combine like terms: -12i + 12i = 0
(8 + 0 + -18i2) = 0
(8 + -18i2) = 0

Solving
8 + -18i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -18i2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -18i2 = 0 + -8
-18i2 = 0 + -8

Combine like terms: 0 + -8 = -8
-18i2 = -8

Divide each side by '-18'.
i2 = 0.4444444444

Simplifying
i2 = 0.4444444444

Take the square root of each side:
i = {-0.666666667, 0.666666667}