(4+5i)(12+11i)=0

Solution for (4+5i)(12+11i)=0 equation:

(4+5i)(12+11i)=0

We add all the numbers together, and all the variables

(5i+4)(11i+12)=0

We multiply parentheses ..

(+55i^2+60i+44i+48)=0

We get rid of parentheses

55i^2+60i+44i+48=0

We add all the numbers together, and all the variables

55i^2+104i+48=0

a = 55; b = 104; c = +48;
Δ = b2-4ac
Δ = 1042-4·55·48
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-16}{2*55}=\frac{-120}{110}
=-1+1/11
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+16}{2*55}=\frac{-88}{110}
=-4/5
$