(4+3i)+(2+2i)=

Solution for (4+3i)+(2+2i)= equation:

Simplifying
(4 + 3i) + (2 + 2i) = 0

Remove parenthesis around (4 + 3i)
4 + 3i + (2 + 2i) = 0

Remove parenthesis around (2 + 2i)
4 + 3i + 2 + 2i = 0

Reorder the terms:
4 + 2 + 3i + 2i = 0

Combine like terms: 4 + 2 = 6
6 + 3i + 2i = 0

Combine like terms: 3i + 2i = 5i
6 + 5i = 0

Solving
6 + 5i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 5i = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 5i = 0 + -6
5i = 0 + -6

Combine like terms: 0 + -6 = -6
5i = -6

Divide each side by '5'.
i = -1.2

Simplifying
i = -1.2