(4+3i)(x+yi)=1

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Solution for (4+3i)(x+yi)=1 equation: 


Simplifying
(4 + 3i)(x + yi) = 1

Reorder the terms:
(4 + 3i)(iy + x) = 1

Multiply (4 + 3i) * (iy + x)
(4(iy + x) + 3i * (iy + x)) = 1
((iy * 4 + x * 4) + 3i * (iy + x)) = 1
((4iy + 4x) + 3i * (iy + x)) = 1
(4iy + 4x + (iy * 3i + x * 3i)) = 1

Reorder the terms:
(4iy + 4x + (3ix + 3i2y)) = 1
(4iy + 4x + (3ix + 3i2y)) = 1

Reorder the terms:
(3ix + 4iy + 3i2y + 4x) = 1
(3ix + 4iy + 3i2y + 4x) = 1

Solving
3ix + 4iy + 3i2y + 4x = 1

Solving for variable 'i'.

Reorder the terms:
-1 + 3ix + 4iy + 3i2y + 4x = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3ix + 4iy + 3i2y + 4x = 0

The solution to this equation could not be determined.

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