If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(4(2x-5)-6)/3=(2x+1)/3-3
We move all terms to the left:
(4(2x-5)-6)/3-((2x+1)/3-3)=0
We calculate fractions
=0
x=0/1
x=0
| 61+90y=180 | | d+(d+8)=40 | | x2+18x+16=0 | | 70-3x=35 | | 55-x=30 | | (2-n)=6(2-n) | | b/200=3 | | m-15=-32 | | (60)(5x)=180 | | 25^5x=625 | | 2x+-5x=-14+-7 | | 4x+6=8x-26 | | 2x^2+√3x-8=0 | | 4m–16=-20 | | k/7=5/21 | | Vx=3x | | 8z+24=-16 | | -(x+7)=-5x+21 | | x+8x=3x | | 1/4(x-8)=1/5(2x-1) | | 14x-3x=x-6 | | -x+4=-2(x+7)+2x | | 0.5*x-1.5/x=1.04 | | 2x+24/2=34 | | 42+2x=18 | | 5(0.25x-1)=5/4x-1.4 | | 5(0.25p-1)=5/4p-1.4 | | -5=h+7 | | −7x^2−21x=0 | | −7x2−21x=0 | | 3x/4=5/12 | | 3y-y-5=0 |