(3z-12)+(2z-3)=90

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Solution for (3z-12)+(2z-3)=90 equation: 



(3z-12)+(2z-3)=90

We move all terms to the left:

(3z-12)+(2z-3)-(90)=0

We get rid of parentheses

3z+2z-12-3-90=0

We add all the numbers together, and all the variables

5z-105=0

We move all terms containing z to the left, all other terms to the right

5z=105

z=105/5

z=21

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