(3z-1)=(z+7)

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Solution for (3z-1)=(z+7) equation: 



(3z-1)=(z+7)

We move all terms to the left:

(3z-1)-((z+7))=0

We get rid of parentheses

3z-((z+7))-1=0



We calculate terms in parentheses: -((z+7)), so:

(z+7)

We get rid of parentheses

z+7

Back to the equation:

-(z+7)



We get rid of parentheses

3z-z-7-1=0

We add all the numbers together, and all the variables

2z-8=0

We move all terms containing z to the left, all other terms to the right

2z=8

z=8/2

z=4

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