(3z+5)+(7z+3)=-32

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Solution for (3z+5)+(7z+3)=-32 equation: 



(3z+5)+(7z+3)=-32

We move all terms to the left:

(3z+5)+(7z+3)-(-32)=0

We add all the numbers together, and all the variables

(3z+5)+(7z+3)+32=0

We get rid of parentheses

3z+7z+5+3+32=0

We add all the numbers together, and all the variables

10z+40=0

We move all terms containing z to the left, all other terms to the right

10z=-40

z=-40/10

z=-4

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