(3z+4z)/z=9

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Solution for (3z+4z)/z=9 equation: 



(3z+4z)/z=9

We move all terms to the left:

(3z+4z)/z-(9)=0



Domain of the equation: z!=0

z∈R



We add all the numbers together, and all the variables

(+7z)/z-9=0

We multiply all the terms by the denominator


(+7z)-9*z=0

We add all the numbers together, and all the variables

-9z+(+7z)=0

We get rid of parentheses

-9z+7z=0

We add all the numbers together, and all the variables

-2z=0

z=0/-2

z=0

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