(3z+41)+(z+91)=(-2z+78)*2

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Solution for (3z+41)+(z+91)=(-2z+78)*2 equation: 



(3z+41)+(z+91)=(-2z+78)*2

We move all terms to the left:

(3z+41)+(z+91)-((-2z+78)*2)=0

We get rid of parentheses

3z+z-((-2z+78)*2)+41+91=0



We calculate terms in parentheses: -((-2z+78)*2), so:

(-2z+78)*2

We multiply parentheses

-4z+156

Back to the equation:

-(-4z+156)



We add all the numbers together, and all the variables

4z-(-4z+156)+132=0

We get rid of parentheses

4z+4z-156+132=0

We add all the numbers together, and all the variables

8z-24=0

We move all terms containing z to the left, all other terms to the right

8z=24

z=24/8

z=3

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