(3z+1)=(2z-3)+(12)

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Solution for (3z+1)=(2z-3)+(12) equation:


Simplifying
(3z + 1) = (2z + -3) + (12)

Reorder the terms:
(1 + 3z) = (2z + -3) + (12)

Remove parenthesis around (1 + 3z)
1 + 3z = (2z + -3) + (12)

Reorder the terms:
1 + 3z = (-3 + 2z) + (12)

Remove parenthesis around (-3 + 2z)
1 + 3z = -3 + 2z + (12)
1 + 3z = -3 + 2z + 12

Reorder the terms:
1 + 3z = -3 + 12 + 2z

Combine like terms: -3 + 12 = 9
1 + 3z = 9 + 2z

Solving
1 + 3z = 9 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
1 + 3z + -2z = 9 + 2z + -2z

Combine like terms: 3z + -2z = 1z
1 + 1z = 9 + 2z + -2z

Combine like terms: 2z + -2z = 0
1 + 1z = 9 + 0
1 + 1z = 9

Add '-1' to each side of the equation.
1 + -1 + 1z = 9 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 9 + -1
1z = 9 + -1

Combine like terms: 9 + -1 = 8
1z = 8

Divide each side by '1'.
z = 8

Simplifying
z = 8

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