(3z+1)+(2z+1)=48

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Solution for (3z+1)+(2z+1)=48 equation:


Simplifying
(3z + 1) + (2z + 1) = 48

Reorder the terms:
(1 + 3z) + (2z + 1) = 48

Remove parenthesis around (1 + 3z)
1 + 3z + (2z + 1) = 48

Reorder the terms:
1 + 3z + (1 + 2z) = 48

Remove parenthesis around (1 + 2z)
1 + 3z + 1 + 2z = 48

Reorder the terms:
1 + 1 + 3z + 2z = 48

Combine like terms: 1 + 1 = 2
2 + 3z + 2z = 48

Combine like terms: 3z + 2z = 5z
2 + 5z = 48

Solving
2 + 5z = 48

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5z = 48 + -2

Combine like terms: 2 + -2 = 0
0 + 5z = 48 + -2
5z = 48 + -2

Combine like terms: 48 + -2 = 46
5z = 46

Divide each side by '5'.
z = 9.2

Simplifying
z = 9.2

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