(3y/8)=(50+y)/6

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Solution for (3y/8)=(50+y)/6 equation: 



(3y/8)=(50+y)/6

We move all terms to the left:

(3y/8)-((50+y)/6)=0

We add all the numbers together, and all the variables

(+3y/8)-((y+50)/6)=0

We get rid of parentheses

3y/8-((y+50)/6)=0

We calculate fractions


18y^2/()+(-((y+50)*8)/()=0



We calculate terms in parentheses: +(-((y+50)*8)/(), so:

-((y+50)*8)/(

We multiply all the terms by the denominator


-((y+50)*8)



We calculate terms in parentheses: -((y+50)*8), so:

(y+50)*8

We multiply parentheses

8y+400

Back to the equation:

-(8y+400)



We get rid of parentheses

-8y-400

Back to the equation:

+(-8y-400)



We get rid of parentheses

18y^2/()-8y-400=0

We multiply all the terms by the denominator


18y^2-8y*()-400*()=0

We add all the numbers together, and all the variables

18y^2-8y*()=0

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