(3y/4)-(2y/7)=1

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Solution for (3y/4)-(2y/7)=1 equation: 


y in (-oo:+oo)

(3*y)/4-((2*y)/7) = 1 // - 1

(3*y)/4-((2*y)/7)-1 = 0

(3*y)/4+(-2/7)*y-1 = 0

13/28*y-1 = 0 // + 1

13/28*y = 1 // : 13/28

y = 1/13/28

y = 28/13

y = 28/13

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