(3y-6)/9=(4-2y)/(-3)

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Solution for (3y-6)/9=(4-2y)/(-3) equation: 



(3y-6)/9=(4-2y)/(-3)

We move all terms to the left:

(3y-6)/9-((4-2y)/(-3))=0

We add all the numbers together, and all the variables

(3y-6)/9-((-2y+4)/(-3))=0

We calculate fractions


((3y-6)*(-3)))/()+(-((-2y+4)*9)/()=0



We calculate terms in parentheses: -((-2y+4)*9)/(), so:

(-2y+4)*9)/(

We multiply all the terms by the denominator


(-2y+4)*9)

We get rid of parentheses

-2y+4)*9

We add all the numbers together, and all the variables

-2y

Back to the equation:

-(-2y)



We get rid of parentheses

((3y-6)*(-3)))/()+(+2y=0

We multiply all the terms by the denominator


((3y-6)*(-3)))+2y*()+(=0

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