(3y-6)/(2y)=17/3

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Solution for (3y-6)/(2y)=17/3 equation: 



(3y-6)/(2y)=17/3

We move all terms to the left:

(3y-6)/(2y)-(17/3)=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

(3y-6)/2y-(+17/3)=0

We get rid of parentheses

(3y-6)/2y-17/3=0

We calculate fractions


(9y-18)/6y+(-34y)/6y=0

We multiply all the terms by the denominator


(9y-18)+(-34y)=0

We get rid of parentheses

9y-34y-18=0

We add all the numbers together, and all the variables

-25y-18=0

We move all terms containing y to the left, all other terms to the right

-25y=18

y=18/-25

y=-18/25

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