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(3y-5)/(2y+1)=3/4
We move all terms to the left:
(3y-5)/(2y+1)-(3/4)=0
Domain of the equation: (2y+1)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
2y!=-1
y!=-1/2
y!=-1/2
y∈R
(3y-5)/(2y+1)-(+3/4)=0
We get rid of parentheses
(3y-5)/(2y+1)-3/4=0
We calculate fractions
(12y-20)/(8y+4)+(-6y-3)/(8y+4)=0
We multiply all the terms by the denominator
(12y-20)+(-6y-3)=0
We get rid of parentheses
12y-6y-20-3=0
We add all the numbers together, and all the variables
6y-23=0
We move all terms containing y to the left, all other terms to the right
6y=23
y=23/6
y=3+5/6
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