(3y-5)+(5y+2)=135

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Solution for (3y-5)+(5y+2)=135 equation: 



(3y-5)+(5y+2)=135

We move all terms to the left:

(3y-5)+(5y+2)-(135)=0

We get rid of parentheses

3y+5y-5+2-135=0

We add all the numbers together, and all the variables

8y-138=0

We move all terms containing y to the left, all other terms to the right

8y=138

y=138/8

y=17+1/4

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