(3y-4)-(7y+1)=0

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Solution for (3y-4)-(7y+1)=0 equation:


Simplifying
(3y + -4) + -1(7y + 1) = 0

Reorder the terms:
(-4 + 3y) + -1(7y + 1) = 0

Remove parenthesis around (-4 + 3y)
-4 + 3y + -1(7y + 1) = 0

Reorder the terms:
-4 + 3y + -1(1 + 7y) = 0
-4 + 3y + (1 * -1 + 7y * -1) = 0
-4 + 3y + (-1 + -7y) = 0

Reorder the terms:
-4 + -1 + 3y + -7y = 0

Combine like terms: -4 + -1 = -5
-5 + 3y + -7y = 0

Combine like terms: 3y + -7y = -4y
-5 + -4y = 0

Solving
-5 + -4y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -4y = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -4y = 0 + 5
-4y = 0 + 5

Combine like terms: 0 + 5 = 5
-4y = 5

Divide each side by '-4'.
y = -1.25

Simplifying
y = -1.25

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