(3y-4)+y=16

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Solution for (3y-4)+y=16 equation: 



(3y-4)+y=16

We move all terms to the left:

(3y-4)+y-(16)=0

We add all the numbers together, and all the variables

y+(3y-4)-16=0

We get rid of parentheses

y+3y-4-16=0

We add all the numbers together, and all the variables

4y-20=0

We move all terms containing y to the left, all other terms to the right

4y=20

y=20/4

y=5

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