(3y-2)1/5=6

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Solution for (3y-2)1/5=6 equation: 


y in (-oo:+oo)

((3*y-2)^1)/5 = 6 // - 6

((3*y-2)^1)/5-6 = 0

(3*y-2)/5-6 = 0

(3*y-2)/5+(-6*5)/5 = 0

3*y-6*5-2 = 0

3*y-32 = 0

(3*y-32)/5 = 0

(3*y-32)/5 = 0 // * 5

3*y-32 = 0

3*y-32 = 0 // + 32

3*y = 32 // : 3

y = 32/3

y = 32/3

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