(3y-2)/(y+1)=4-(y+2)/(y-1)

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Solution for (3y-2)/(y+1)=4-(y+2)/(y-1) equation:


D( y )

y-1 = 0

y+1 = 0

y-1 = 0

y-1 = 0

y-1 = 0 // + 1

y = 1

y+1 = 0

y+1 = 0

y+1 = 0 // - 1

y = -1

y in (-oo:-1) U (-1:1) U (1:+oo)

(3*y-2)/(y+1) = 4-((y+2)/(y-1)) // - 4-((y+2)/(y-1))

(3*y-2)/(y+1)+(y+2)/(y-1)-4 = 0

((3*y-2)*(y-1))/((y+1)*(y-1))+((y+2)*(y+1))/((y+1)*(y-1))+(-4*(y+1)*(y-1))/((y+1)*(y-1)) = 0

(3*y-2)*(y-1)+(y+2)*(y+1)-4*(y+1)*(y-1) = 0

4*y^2-4*y^2-2*y+4+4 = 0

8-2*y = 0

(8-2*y)/((y+1)*(y-1)) = 0

(8-2*y)/((y+1)*(y-1)) = 0 // * (y+1)*(y-1)

8-2*y = 0

8-2*y = 0 // - 8

-2*y = -8 // : -2

y = -8/(-2)

y = 4

y = 4

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