(3y-1/2)=7

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Solution for (3y-1/2)=7 equation: 



(3y-1/2)=7

We move all terms to the left:

(3y-1/2)-(7)=0

We add all the numbers together, and all the variables

(+3y-1/2)-7=0

We get rid of parentheses

3y-7-1/2=0

We multiply all the terms by the denominator


3y*2-1-7*2=0

We add all the numbers together, and all the variables

3y*2-15=0

Wy multiply elements

6y-15=0

We move all terms containing y to the left, all other terms to the right

6y=15

y=15/6

y=2+1/2

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