(3y-1)+(4y-4)=90

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Solution for (3y-1)+(4y-4)=90 equation: 



(3y-1)+(4y-4)=90

We move all terms to the left:

(3y-1)+(4y-4)-(90)=0

We get rid of parentheses

3y+4y-1-4-90=0

We add all the numbers together, and all the variables

7y-95=0

We move all terms containing y to the left, all other terms to the right

7y=95

y=95/7

y=13+4/7

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