(3y+7)+(2y+6)+(4y+3)=106

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Solution for (3y+7)+(2y+6)+(4y+3)=106 equation: 



(3y+7)+(2y+6)+(4y+3)=106

We move all terms to the left:

(3y+7)+(2y+6)+(4y+3)-(106)=0

We get rid of parentheses

3y+2y+4y+7+6+3-106=0

We add all the numbers together, and all the variables

9y-90=0

We move all terms containing y to the left, all other terms to the right

9y=90

y=90/9

y=10

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