(3y+5)=(4y-30)

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Solution for (3y+5)=(4y-30) equation: 



(3y+5)=(4y-30)

We move all terms to the left:

(3y+5)-((4y-30))=0

We get rid of parentheses

3y-((4y-30))+5=0



We calculate terms in parentheses: -((4y-30)), so:

(4y-30)

We get rid of parentheses

4y-30

Back to the equation:

-(4y-30)



We get rid of parentheses

3y-4y+30+5=0

We add all the numbers together, and all the variables

-1y+35=0

We move all terms containing y to the left, all other terms to the right

-y=-35

y=-35/-1

y=+35

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