(3y+4)(1+y)=0

Solution for (3y+4)(1+y)=0 equation:

Simplifying
(3y + 4)(1 + y) = 0

Reorder the terms:
(4 + 3y)(1 + y) = 0

Multiply (4 + 3y) * (1 + y)
(4(1 + y) + 3y * (1 + y)) = 0
((1 * 4 + y * 4) + 3y * (1 + y)) = 0
((4 + 4y) + 3y * (1 + y)) = 0
(4 + 4y + (1 * 3y + y * 3y)) = 0
(4 + 4y + (3y + 3y2)) = 0

Combine like terms: 4y + 3y = 7y
(4 + 7y + 3y2) = 0

Solving
4 + 7y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + 3y)(1 + y) = 0

Subproblem 1
Set the factor '(4 + 3y)' equal to zero and attempt to solve:

Simplifying
4 + 3y = 0

Solving
4 + 3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 3y = 0 + -4
3y = 0 + -4

Combine like terms: 0 + -4 = -4
3y = -4

Divide each side by '3'.
y = -1.333333333

Simplifying
y = -1.333333333
Subproblem 2
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Solution
y = {-1.333333333, -1}