(3y+33)=(9y+21)

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Solution for (3y+33)=(9y+21) equation: 



(3y+33)=(9y+21)

We move all terms to the left:

(3y+33)-((9y+21))=0

We get rid of parentheses

3y-((9y+21))+33=0



We calculate terms in parentheses: -((9y+21)), so:

(9y+21)

We get rid of parentheses

9y+21

Back to the equation:

-(9y+21)



We get rid of parentheses

3y-9y-21+33=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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