(3y+3)-7=(1y-12)

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Solution for (3y+3)-7=(1y-12) equation:


Simplifying
(3y + 3) + -7 = (1y + -12)

Reorder the terms:
(3 + 3y) + -7 = (1y + -12)

Remove parenthesis around (3 + 3y)
3 + 3y + -7 = (1y + -12)

Reorder the terms:
3 + -7 + 3y = (1y + -12)

Combine like terms: 3 + -7 = -4
-4 + 3y = (1y + -12)

Reorder the terms:
-4 + 3y = (-12 + 1y)

Remove parenthesis around (-12 + 1y)
-4 + 3y = -12 + 1y

Solving
-4 + 3y = -12 + 1y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
-4 + 3y + -1y = -12 + 1y + -1y

Combine like terms: 3y + -1y = 2y
-4 + 2y = -12 + 1y + -1y

Combine like terms: 1y + -1y = 0
-4 + 2y = -12 + 0
-4 + 2y = -12

Add '4' to each side of the equation.
-4 + 4 + 2y = -12 + 4

Combine like terms: -4 + 4 = 0
0 + 2y = -12 + 4
2y = -12 + 4

Combine like terms: -12 + 4 = -8
2y = -8

Divide each side by '2'.
y = -4

Simplifying
y = -4

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