(3y+3)(y+4)=

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Solution for (3y+3)(y+4)= equation:


Simplifying
(3y + 3)(y + 4) = 0

Reorder the terms:
(3 + 3y)(y + 4) = 0

Reorder the terms:
(3 + 3y)(4 + y) = 0

Multiply (3 + 3y) * (4 + y)
(3(4 + y) + 3y * (4 + y)) = 0
((4 * 3 + y * 3) + 3y * (4 + y)) = 0
((12 + 3y) + 3y * (4 + y)) = 0
(12 + 3y + (4 * 3y + y * 3y)) = 0
(12 + 3y + (12y + 3y2)) = 0

Combine like terms: 3y + 12y = 15y
(12 + 15y + 3y2) = 0

Solving
12 + 15y + 3y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '3'.
3(4 + 5y + y2) = 0

Factor a trinomial.
3((4 + y)(1 + y)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(4 + y)' equal to zero and attempt to solve: Simplifying 4 + y = 0 Solving 4 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + y = 0 + -4 y = 0 + -4 Combine like terms: 0 + -4 = -4 y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(1 + y)' equal to zero and attempt to solve: Simplifying 1 + y = 0 Solving 1 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + y = 0 + -1 y = 0 + -1 Combine like terms: 0 + -1 = -1 y = -1 Simplifying y = -1

Solution

y = {-4, -1}

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