(3y+27)=(8y-28)

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Solution for (3y+27)=(8y-28) equation: 



(3y+27)=(8y-28)

We move all terms to the left:

(3y+27)-((8y-28))=0

We get rid of parentheses

3y-((8y-28))+27=0



We calculate terms in parentheses: -((8y-28)), so:

(8y-28)

We get rid of parentheses

8y-28

Back to the equation:

-(8y-28)



We get rid of parentheses

3y-8y+28+27=0

We add all the numbers together, and all the variables

-5y+55=0

We move all terms containing y to the left, all other terms to the right

-5y=-55

y=-55/-5

y=+11

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