(3y+2)=(y+20)

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Solution for (3y+2)=(y+20) equation: 



(3y+2)=(y+20)

We move all terms to the left:

(3y+2)-((y+20))=0

We get rid of parentheses

3y-((y+20))+2=0



We calculate terms in parentheses: -((y+20)), so:

(y+20)

We get rid of parentheses

y+20

Back to the equation:

-(y+20)



We get rid of parentheses

3y-y-20+2=0

We add all the numbers together, and all the variables

2y-18=0

We move all terms containing y to the left, all other terms to the right

2y=18

y=18/2

y=9

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