(3y+2)-3(2y+3)=12

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Solution for (3y+2)-3(2y+3)=12 equation:


Simplifying
(3y + 2) + -3(2y + 3) = 12

Reorder the terms:
(2 + 3y) + -3(2y + 3) = 12

Remove parenthesis around (2 + 3y)
2 + 3y + -3(2y + 3) = 12

Reorder the terms:
2 + 3y + -3(3 + 2y) = 12
2 + 3y + (3 * -3 + 2y * -3) = 12
2 + 3y + (-9 + -6y) = 12

Reorder the terms:
2 + -9 + 3y + -6y = 12

Combine like terms: 2 + -9 = -7
-7 + 3y + -6y = 12

Combine like terms: 3y + -6y = -3y
-7 + -3y = 12

Solving
-7 + -3y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -3y = 12 + 7

Combine like terms: -7 + 7 = 0
0 + -3y = 12 + 7
-3y = 12 + 7

Combine like terms: 12 + 7 = 19
-3y = 19

Divide each side by '-3'.
y = -6.333333333

Simplifying
y = -6.333333333

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