(3y+2)+(2y+6)=9y-12

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Solution for (3y+2)+(2y+6)=9y-12 equation: 



(3y+2)+(2y+6)=9y-12

We move all terms to the left:

(3y+2)+(2y+6)-(9y-12)=0

We get rid of parentheses

3y+2y-9y+2+6+12=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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